<HTML><HEAD></HEAD><BODY><font face="Courier New" size=2>Oh
boy - so genius simple.. :-) <BR></font><BR>vbr Carsten
<BR><BR>"Dan H." <<A
href="mailto:jumachine@comcast.net">jumachine@comcast.net</a>>
schrieb:<BR>> How to solve the problem of depth figuring in on the
situation is to use <BR>> double ended cylinders. With a rod of the
same size sticking out of each <BR>> end of each cylinder the effect
of water pressure balances out. The force <BR>> is the same in
either direction.<BR>> <BR>> Dan H.<BR>> <BR>> -----
Original Message ----- <BR>> From: "hank pronk" <<A
href="mailto:hanker_20032000@yahoo.ca">hanker_20032000@yahoo.ca</a>><BR>>
To: "Personal Submersibles General Discussion" <BR>> <<A
href="mailto:personal_submersibles@psubs.org">personal_submersibles@psubs.org</a>><BR>>
Sent: Saturday, April 12, 2014 8:58 AM<BR>> Subject: Re:
[PSUBS-MAILIST] new submarine inside to outside hydraulic<BR>>
<BR>> <BR>> Hi Carsten,<BR>> I am not sure about your math, I
get a much different figure.<BR>> A 1/2 in rod has an area of
.19in<BR>> multiply by 1,000 foot depth salt water 445psi = 87.33
lbs<BR>> With a 10 to 1 lever that would be 8.7 lbs to push with your
arm.<BR>> Also you want a smaller cylinder inside with a longer
stroke and you get an <BR>> even lighter load on your arm.<BR>>
Hank<BR>> <BR>> Subject: Re: [PSUBS-MAILIST] new submarine inside
to outside hydraulic<BR>> To: "Personal Submersibles General
Discussion" <BR>> <<A
href="mailto:personal_submersibles@psubs.org">personal_submersibles@psubs.org</a>><BR>>
Received: Saturday, April 12, 2014, 2:56 AM<BR>> <BR>> <BR>>
<BR>> <BR>> <BR>> E-Mail Software 6.0<BR>> <BR>> Hi
Scott,<BR>> <BR>> 1 bar = 0,1<BR>> N/mm2<BR>> <BR>>
1000 meter depth = 100 bar or 10 N/mm2<BR>> (or 1<BR>>
kg/mm2)<BR>> <BR>> A Hydraulic stamp of a 1/2 inch has a surface
of 126<BR>> <BR>> mm2<BR>> means the outside waterpressure on
the cylinder stamp is<BR>> 1267<BR>> N or<BR>> 127 Kg or
0,13 ts.<BR>> <BR>> If you make a drawing of your schematic
you<BR>> will see<BR>> that it is not selfcompensating.<BR>>
Means you need a inside force of<BR>> that<BR>> amout just to
compensate.<BR>> If you asume you can take a pressure<BR>> of
0,013<BR>> ts<BR>> with some comfore by hand you inside zylinder
piston has to<BR>> be<BR>> the 10<BR>> times more diameter
thn the outside one.<BR>> <BR>> By the way the same<BR>>
force works<BR>> on your troughulls cables of the same
diameter.<BR>> <BR>> vbr Carsten<BR>> <BR>> <BR>>
<BR>> <BR>> <<A
href="mailto:swaters@waters-ks.com">swaters@waters-ks.com</a>>
schrieb:<BR>> <BR>> I have a question maybe someone can
answer.<BR>> If you have two hydraulic cylinders that are
completely<BR>> filled with<BR>> oil (no air pockets anywhere in
the system) one in a<BR>> submarine and on<BR>> outside of a
submarine. Each cylinder has the rod side<BR>> connected to
the<BR>> head side of the other cylinder so when on rod extends,
the<BR>> flow of one<BR>> makes the other cylinder do the same
exact thing. Would the<BR>> one cylinder<BR>> that does the same
as the other cylinder on the surface<BR>> function the<BR>> same
way at depth? Or would the deeper you go the more force<BR>> you
would<BR>> have trying to push the rod into the cylinder?<BR>>
<BR>> Thanks,<BR>> Scott Waters<BR>> <BR>> <BR>>
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