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<DIV><FONT size=2 face=Arial>Nope! Just experienced...... LOL
Ben there</FONT></DIV>
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<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black"><B>From:</B>
<A title=swaters@waters-ks.com href="mailto:swaters@waters-ks.com">swaters</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A
title=personal_submersibles@psubs.org
href="mailto:personal_submersibles@psubs.org">Personal Submersibles General
Discussion</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Saturday, April 12, 2014 6:47
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [PSUBS-MAILIST] new
submarine inside to outside hydraulic</DIV>
<DIV><BR></DIV>
<DIV>Dan,</DIV>
<DIV>You are brilliant!</DIV>
<DIV>Thanks,</DIV>
<DIV>Scott Waters</DIV>
<DIV><BR></DIV>
<DIV><BR></DIV>
<DIV><BR></DIV>
<DIV><BR></DIV>
<DIV>
<DIV style="COLOR: #575757; FONT-SIZE: 75%">Sent from my U.S. Cellular©
Smartphone</DIV></DIV><BR>"Dan H." <<A
href="mailto:jumachine@comcast.net">jumachine@comcast.net</A>>
wrote:<BR>How to solve the problem of depth figuring in on the situation is to
use <BR>double ended cylinders. With a rod of the same size sticking out
of each <BR>end of each cylinder the effect of water pressure balances
out. The force <BR>is the same in either direction.<BR><BR>Dan
H.<BR><BR>----- Original Message ----- <BR>From: "hank pronk"
<hanker_20032000@yahoo.ca><BR>To: "Personal Submersibles General
Discussion" <BR><personal_submersibles@psubs.org><BR>Sent: Saturday,
April 12, 2014 8:58 AM<BR>Subject: Re: [PSUBS-MAILIST] new submarine inside to
outside hydraulic<BR><BR><BR>Hi Carsten,<BR>I am not sure about your math, I
get a much different figure.<BR>A 1/2 in rod has an area of .19in<BR>multiply
by 1,000 foot depth salt water 445psi = 87.33 lbs<BR>With a 10 to 1 lever that
would be 8.7 lbs to push with your arm.<BR>Also you want a smaller cylinder
inside with a longer stroke and you get an <BR>even lighter load on your
arm.<BR>Hank<BR><BR>Subject: Re: [PSUBS-MAILIST] new submarine inside to
outside hydraulic<BR>To: "Personal Submersibles General Discussion"
<BR><personal_submersibles@psubs.org><BR>Received: Saturday, April 12,
2014, 2:56 AM<BR><BR><BR><BR><BR><BR>E-Mail Software 6.0<BR><BR>Hi
Scott,<BR><BR>1 bar = 0,1<BR>N/mm2<BR><BR>1000 meter depth = 100 bar or 10
N/mm2<BR>(or 1<BR>kg/mm2)<BR><BR>A Hydraulic stamp of a 1/2 inch has a surface
of 126<BR><BR>mm2<BR>means the outside waterpressure on the cylinder stamp
is<BR>1267<BR>N or<BR>127 Kg or 0,13 ts.<BR><BR>If you make a drawing of your
schematic you<BR>will see<BR>that it is not selfcompensating.<BR>Means you
need a inside force of<BR>that<BR>amout just to compensate.<BR>If you asume
you can take a pressure<BR>of 0,013<BR>ts<BR>with some comfore by hand you
inside zylinder piston has to<BR>be<BR>the 10<BR>times more diameter thn the
outside one.<BR><BR>By the way the same<BR>force works<BR>on your troughulls
cables of the same diameter.<BR><BR>vbr
Carsten<BR><BR><BR><BR><BR><swaters@waters-ks.com> schrieb:<BR><BR>I
have a question maybe someone can answer.<BR>If you have two hydraulic
cylinders that are completely<BR>filled with<BR>oil (no air pockets anywhere
in the system) one in a<BR>submarine and on<BR>outside of a submarine. Each
cylinder has the rod side<BR>connected to the<BR>head side of the other
cylinder so when on rod extends, the<BR>flow of one<BR>makes the other
cylinder do the same exact thing. Would the<BR>one cylinder<BR>that does the
same as the other cylinder on the surface<BR>function the<BR>same way at
depth? Or would the deeper you go the more force<BR>you would<BR>have trying
to push the rod into the cylinder?<BR><BR>Thanks,<BR>Scott
Waters<BR><BR><BR><BR><BR>-----Inline Attachment
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