<html>
<head>
<meta content="text/html; charset=ISO-8859-1"
http-equiv="Content-Type">
</head>
<body bgcolor="#FFFFFF" text="#000000">
<div class="moz-cite-prefix">I just wanted to point out that with a
single-rod double-acting cylinder, the flow out is not equivalent
to the flow in for any given stroke, owing to the unequal areas as
a result of the rod on one side. The only way this would work is
to connect head end to head end, rod end to rod end, in which case
the direction of stroke would be reversed. Alternatively, a
cylinder with a rod on each side would eliminate both that problem
and the pressure compensation problem.<br>
<br>
Sean<br>
<br>
<br>
On 2014-04-11 13:16, <a class="moz-txt-link-abbreviated" href="mailto:swaters@waters-ks.com">swaters@waters-ks.com</a> wrote:<br>
</div>
<blockquote
cite="mid:20140411121659.49e8347f125ba4e1b2aff75c01b07c1e.453bd9bd3b.wbe@email13.secureserver.net"
type="cite"><span style="font-family:Verdana; color:#000000;
font-size:10pt;">
<div>I have a question maybe someone can answer.</div>
<div>If you have two hydraulic cylinders that are completely
filled with oil (no air pockets anywhere in the system) one in
a submarine and on outside of a submarine. Each cylinder has
the rod side connected to the head side of the other cylinder
so when on rod extends, the flow of one makes the other
cylinder do the same exact thing. Would the one cylinder that
does the same as the other cylinder on the surface function
the same way at depth? Or would the deeper you go the more
force you would have trying to push the rod into the cylinder?
</div>
<div> </div>
<div>Thanks,</div>
<div>Scott Waters </div>
</span>
</blockquote>
<br>
</body>
</html>